# How Many Four Digit Numbers Can Be Formed From The Digits 12345

6p4=6!/2!=360 numbers. Pi - Verification. First digit odd: 3 digits. Place value blocks (base 10 blocks) and expanded form. 35 x 10 4) example: Round to 2 significant figures: 1. So 4 numbers. Apr 15,2020 - How many even numbers of four digits can be formed with the digits 1, 2, 3, 4, 5, 6 (repetitions of digits are allowed)?a)648b)180c)1296d)600Correct. As can the third. 3, 4 (Method 1)Find the number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated. digits cannot be repeated? Using the Fundamental Counting Principle: 2. Therefore, there will be 4 ways to fill the second spot, 3 ways to fill the third, and so on. For example, the base 2 numeral 10. Practice writing numbers in expanded notation, ordering from greatest to least, counting base-10 place value blocks, and more. Question: How many 6-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 if repetitions are allowed? Permutations with Repetition:. You can put this solution on YOUR website! If repetition is allowed, how many three-digit numbers can be formed using the digits 1, 2, 3, 4, 5, 6? We can pick the. Here, we have made 6 sets of numbers. Once you choose that first digit, you have three choices for the second digit. 139 173 179 193 197 317 379 397 719 739 937 971. I have numbers like 1100, 1002, 1022 etc. With that knowledge, we know that there are 5 ways of filling up the thousands-digit, 4 ways for the hundreds-digits, 3 ways for the tens-digit, and 2 ways for the ones-digit. Many countries in Europe use another system. The hints above describe two possible numbers. Yay pi i memorised the first 9 digits of pi from a calculator at school in maths when i was 13 and carried on learning to 27 digits, meerly to beat the class know it all, ive now only at 15 began to learn again as ive noticed the facination in pi and the grouped numbers. For the first digit we have 4 choices and for the second digit we have 3 choices (4 - 1 used already). 5-digit number is to be formed from the digits 1, 2, 3, 4, 5, 6, 7, 8, 9. For a number to be multiple of 3, sum of digits should be multiple of 3. To ask Unlimited Maths doubts download Doubtnut from - https://goo. How many four digit numbers greater than $5000$ can be formed by using the digits $4$, $5$, $6$ and $7$?( Repetition of the digits is not allowed) According to me answer should be 24 Thousand pla. If we change the order to 207, this represents a. For the first digit, you have four choices: 2, 3, 4, or 5. digits cannot be repeated? Using the Fundamental Counting Principle: 2. Suppose that you are going to write one of these 4 digit combinations. 54 + 27 + 54 = 135 total 3-digit numbers where there are no odds touching. Each digit is an odd number. Using Factorial for Class 3 seems difficult. To divide a number by 2, simply shift the number to the right by one digit. The number of six digit numbers that you can make from ten different digits if repetitions of same digit on the six digit number is allowed is 1 000 000 numbers (including number 000 000). of ways =240and last digit = 6, total no. 4 digit number, OK! 3. You can put this solution on YOUR website! 2,4,6,7,8,9 We choose the fourth digit first: There are 2 ways to select the fourth digit, either 7 or 9, so that the number will be odd. Numbers, Numerals and Digits. so we can take these two digits. {eq}\therefore {/eq} We can form 120 four digit numbers greater than 1000. That is, the number of possible combinations is 10*10*10*10 or 10^4, which is equal to 10,000. The 5th digit is chosen from the remaining 6 numbers. 5! = 120 Let's imagine that we've got the five digits and have them scattered about, with the different places (ones, tens, hundreds, thousands, ten thousands) open and ready to accept a digit. For the thousand place we have 5 options (1,2,3,4,5 ). The number of such numbers beginning with '0'. Now, the first 2 digits of the 4 digit number can be filled in 5 x 5 ways as each place can be filled by 5 digits with repetition so max is 5x5=25 cases for each of 5 cases of last 2 digits So, desired answer = 5 x 5 x 5= 125 (answer). Now we can form those unknown two position 2^5 way (number can be repeated. Similarly for 4 and 6 When last digit = 4, total no. of digits of the number to be formed at run-time). 1 - digit numbers - 4. First digit odd: 3 digits. For 4-digit even number, last digit has to be even. As repetition is allowed, the second digit can also take 7 distinct values, and the. Example 3: How many 2 digit numbers can you make using the digits 1, 2, 3 and 4 without repeating the digits? This time we want to use 2 digits at the time to make 2 digit numbers. You have to justify if this assumption is valid. Start : 6:19 PM (JST) May 4, 2010. How many 5 digit numbers can be made from the digits 1,3,4,6,7,8,9 if the 4 and 6 must be used at least once. How many five-digit odd numbers can be formed from the digits 1, 2, 3, 4, and 5 if no digit is repeated? Five digit in place value chart means: Ten thousand-Thousand. 23453428 is divisible by 4 options are a). There are 120 ways to form 4-digit even numbers from the given digits. 134 = 8 C 1 + 8 C 3 + 8 C 4. The primary advantage of PBXs was cost savings on internal phone calls: handling the. Why they are adding $1+2+5+6$?. There are four ways to form such a number. Number > 30000 2. So, there will be 4 × 4! numbers = 4 × 24 = 96 numbers. using 5 digits i. That is, the number of possible combinations is 10*10*10*10 or 10^4, which is equal to 10,000. The total ways to arrange them without repeating a number would be 5 x 4 x 3 = 60 ways. If no repetitions of the the same digit are allowed then you. 2) You need to verify with the first 4 digits: To convert the number to a string, use the TEXT() Function: Value = 2 TEXT(Value, "00") = 02. How many 4-digit numbers can be formed using only the digits {1,2,3} if repetition is allowed and the number must contain the digit 3 somewhere. Explanation: The given digits are six. In how many such integers is the digit $1$ to the left of the digit $2$? RektTheNoob Sep 7, 2017. There are only 5 numbers (or b-ball player) and you can choose to arrange only 3 of them in any order. The MegaPenny Project shows you lots and lots of pennies, up to one quintillion! And there's a chart showing how to name numbers up to 1 followed by 120 zeros. first place can be filled in 3 ways , 2nd place in 4 ways , 3rd in four ways and the fourth in four ways Total such numbers = 3 x 4 x 4 x 4 = 192 Now consider numbers starting with 4 and hundreds place either 1 or 2 (as the number has to be less than 4321) So again for such numbers , first place can be filled in 1 way, 2nd place in 2 ways. 5 choices for the third digit (0 to 4) 5 choices for the fourth digit (0 to 4) 5 choices for the fifth digit (0 to 4) 4 x 5 x 5 x 5 x 5 = 2,500 numbers. the number's last two digits can be any. So, we can already see the benefits of the merger synergies approximately $4 million next quarter. Apart from the stuff given above , if you need any other stuff in math, please use our google custom search here. The 7th digit. For the thousand place we have 5 options (1,2,3,4,5 ). So the total number of 4 digit numbers under these conditions is: 4 X 10 X 10 X 10, or 4000. Similarly for 4 and 6 When last digit = 4, total no. I am also given a list of numbers say {2,4,8,9}. Because they incorporate telephones, the general term “extension” is used to refer to any end point on the branch. For the first digit you are picking from 2 digits. 2, one-tenth is 0. A number is even when its units digit is even. Total possible numbers. Effective Mathematics Tutor. )a)1080b)120c)300d)360Correct answer is option 'D'. 33 digit (any between the digits given different than what we picked for the 1st and 2d digit), 2 opportunities of choosing the fourth digit (any. Therefore, you have10x10x10x10 possible combinations. Q6 How many 4 digit numbers can be formed with different conditions - Duration: Write Smallest Four Digit Number From Given 4 Digits Junior Math - Duration: 3:07. The strings version is approx. That's 10,000. INTRODUCTION1. For the thousand place we have 5 options (1,2,3,4,5 ). There are only 5 numbers (or b-ball player) and you can choose to arrange only 3 of them in any order. 84 1Q20 GAAP Income (Loss) from continuing operations of $(610) million and Operating EBITDA of $1. How many 3 – digit number can be formed from the digit 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is. To form even numbers, units digit should be either 2,4 or 6. // This code is contributed by Anshika Goyal. Question 299130: How many four-digit odd numbers less than 6000 can be formed using the digits 2,4,6,7,8,9? Answer by Edwin McCravy(17789) (Show Source):. you can use any of (1 to 9) 9 digits in 1000's place. see here by using the given digits we can form single digit nos. Once you've chosen the first and second digits, you only have two choices for the third digit. first place can be filled in 3 ways , 2nd place in 4 ways , 3rd in four ways and the fourth in four ways Total such numbers = 3 x 4 x 4 x 4 = 192 Now consider numbers starting with 4 and hundreds place either 1 or 2 (as the number has to be less than 4321) So again for such numbers , first place can be filled in 1 way, 2nd place in 2 ways. 136 is the sum of the cubes of the digits of the sum of the cubes of its digits. To ask Unlimited Maths doubts download Doubtnut from - https://goo. How many 3-digit numbers can be formed from the digits 1,2,3,4 and 5 assuming repetition of digits is allowed. Break the problem down by the number of digits in the answer. The only options we have for the ones digit are 1, 3, 5, 7, and 9 because the digit has to be an odd number. find how many six-digit numbers can be formed from the digits 2,3,4,5,6,7 (with repetitions) if a) numbers formed must be even b) the numbers formed must be divisble by 25 c) the odd digits must occupy even position (2nd, 4th, asked by anna on April 27, 2019; College. How many different 4-digit numbers can be formed from the digits 1, 2, 3, and 4 if A. if the difference of the original number and the new number is 45, find all numbers that satisfy the conditions. If you CAN repeat digits: The first digit can only be 2, 4, 6, or 8, so there are 4 ways to pick the first digit. Apart from the stuff given above , if you need any other stuff in math, please use our google custom search here. How many different four digit numbers can be formed from the digits 1 2 3 4 5 6 from STAT 218 at Ohio State University. 1Q20 GAAP EPS from continuing operations of $(0. So there are 3*6*5*4 even numbers (or 3/7 of the total) and 4*6*5*4 odd numbers (or 4/7 of the total). gl/9WZjCW Using all digits `2,3, 4,5,6` how many even numbers can be formed. How many numbers of three digits can be formed using the digits 1, 2, 3, 4, 5, without repetition of digits is x. how many three digit odd numbers can be formed using the digits 1,2,3,4,5,6 without using any digit more than once? Hi Rebecca, An odd number must not have an even last digit, so from our list of digits to use our last one must be either 1, 3, or 5. and Mike Keith A058908 Six prime numbers in arithmetical progression with a common difference of 9876543210. To ask Unlimited Maths doubts download Doubtnut from - https://goo. RT:How many different four-digit numbers can be formed by rearranging the four digits in 2004?A. Step-by-step explanation: Given : Digits 0,1,2,3,4,5 To find : How many natural numbers less than 1000 can be formed from the digits 0, 1, 2. So last digit is 8, that can be selected in 1 way. Restaurants can also open, provided they practise safe distancing. You have to justify if this assumption is valid. The integer part of the result is the number of digits. Answer: B) 720 Explanation: Let last digit is 2when second last digit is 4 remaining 4 digits can be filled in 120 ways, similarly second last digit is 6 remained 4 digits can be filled in 120 ways. Answer : To form an expression equal to 100 , four plus and minus signs can be inserted between the digits, taken in reverse order, as follows ¬". Find the number of 3-letter passwords that can be formed using the. Well to simplify it , lets consider the Number of places and lets try to figure out what are the possible numbers that can be assigned in each place to make a valid 4 digit number. so the total no of numbers that can be formed are 360 numbers. There are four digits and each of them can be from 0 to 9, for 10 possible choices per digit. Using the digits 1, 2, 3, 4, 5, how many even three-digit numbers less than 500 can be formed if each digit can be used more than once? - 12518721. Ans: 502 9 digit no- 1,2,3,4,5,6,7,8,9 can be formed in only 1 way= 9C0 8 digit no can be formed by taking out one no. For a number to be multiple of 3, sum of digits should be multiple of 3. The 4th digit is chosen from the remaining 7 numbers. "In the face of an unprecedented health, financial, and humanitarian crisis, we are prioritizing the safety and well. (a) We have to find the number of 4-digit numbers that can be formed using the given digits without. is pandigital) in some base b>1. A number is even when its units digit is even. You can put this solution on YOUR website! 2,4,6,7,8,9 We choose the fourth digit first: There are 2 ways to select the fourth digit, either 7 or 9, so that the number will be odd. geno3141 Oct 13, 2015. How many of these will be even?Let. Question: How many 5-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, if repetitions of digits are allowed? Permutations. Using the digits 1, 4, 6, and 9, how many 2-digit whole numbers can be formed if repetitions are not permitted? 5. Find the 4-digit numbers that can be formed using the digits 1,2,3,4,5 if no digit is repeated. RT:How many different four-digit numbers can be formed by rearranging the four digits in 2004?A. You can only use the digits 2, 4, 5, 6, and 7, so eliminate from the numbers above all that contain the digits 0, 1, 3, 8, 9. Now we can form those unknown two position 2^5 way (number can be repeated. Under Type, input "000000000" where there used to be "General" to set minimum number of digits displayed = 9. A square number, also called a perfect square, is a figurate number of the form , where is an integer. That's 10,000. How many four-digit numbers can be formed from the digits 3, 4, 5, 6, 7, 8, if - 2694411. that is (1,3,7,8,9) and (4 ,6) I am going to simplify the question and say that no digit can be used twice and the 4 and 6 must be included. I am also given a list of numbers say {2,4,8,9}. How many three-digit numbers can be formed from the numerals in the set { 1 , 2 , 3 , 4 , 5 } if: a. For example, the base 2 numeral 10. If the first digit is greater than 2 (there are 4 to choose from), then there will be 6x5x4 = 120 permutations for the last 3 digits. Example 3: How many 2 digit numbers can you make using the digits 1, 2, 3 and 4 without repeating the digits? This time we want to use 2 digits at the time to make 2 digit numbers. 4 digit number, OK! 3. If the end digits are 12 then we have 3!=6 ways to choose the first 3 digits. Asked in Math and Arithmetic , Statistics , Algebra. 96 Answer: C 7. 1x4x4x4 = 64. You can use five digits and no digits can repeat, so when you use. A two digit numbers is three times the sum of the digits. asked • 05/05/18 How many 4-digit numbers can be formed using 5, 6, 7 and 8 if the digits cannot be repeated?. For more information about. you can use any of remaining 7 digits in 1's place. 7 4536 numbers can be formed. For a number to be multiple of 3, sum of digits should be multiple of 3. I am given n (the no. Using the digits 1, 4, 6, and 9, how many 2-digit whole numbers can be formed if repetitions are not permitted? 5. And then we can grab one of the remaining 4 digits and place that in the. Always solve it without replacement, unless the problem specifically asks otherwise) Example 4: How many 4-digits number can be formed out of 0,1,2,3,5,7 and 9, if each digit can be used more than once (with repetition). I have to form all the possible numbers that can be formed from the above list of the given length. This can be done by. if you count zero on the first spot to not form a four digit number, then it would be 5*6*6*6, or 1080 four digit numbers. ) "at least 5000" means the number goes from 5000 to 9999, but "divisible by 10" means the form of the number is xxx0, so the last digit is always 0. find how many six-digit numbers can be formed from the digits 2,3,4,5,6,7 (with repetitions) if a) numbers formed must be even b) the numbers formed must be divisble by 25 c) the odd digits must occupy even position (2nd, 4th, asked by anna on April 27, 2019; College. 0 ( 1 Vote ). Rest of the 3 digits can be selected from 1,3 & 7 in 3! ways. This is assuming that no digits are repeated with each combination. How many four digit numbers greater than $5000$ can be formed by using the digits $4$, $5$, $6$ and $7$?( Repetition of the digits is not allowed) According to me answer should be 24 Thousand pla. How many numbers can you make from given a set of individual digits, and how do make it a greatest number? Form all possible three digit number from 0,2 and 6. Question 316914: how many 5 digited odd numbers be formed using the digits 0,1,2,3,4,5 without repetition a)120 b)96 c)56 d)72 e)54 Found 2 solutions by solver91311, fcabanski:. Q6 How many 4 digit numbers can be formed with different conditions - Duration: Write Smallest Four Digit Number From Given 4 Digits Junior Math - Duration: 3:07. Next we choose the second digit: There are 4 ways to select the second digit. 8 - if the number formed by the last 3 digits is divisible by 8. If those numbers are included it brings the count up to 36. The first place can be any of 10 digits. To ask Unlimited Maths doubts download Doubtnut from - https://goo. A two digit numbers is three times the sum of the digits. Now for each of the 100 possible choices of a two digit number you can append any of the ten digits to make a three digit number. Therefore, 5 possibilities exist for the One's digit {1, 3, 5, 7, 9}. of ways of ways of filling the Hundred's place = 4 No. That is, take the digits in descending order, 9 through 1, and form an expression equal to 100 by inserting the smallest possible number of plus and minus signs. How many different four digit numbers can be formed from the digits 1 2 3 4 5 6 from STAT 218 at Ohio State University. How many such four-digit integers are palindromes? Palindromes read the same forward and backward. How many 2-digit whole numbers are there with the units digit being… a) a multiple of 5? b) not a multiple of 5? 3. Hint: it may be easier to first count the numbers that don't contain the digit 3. First digit odd: 3 digits. 0,1,2,3,4,5 can be each in 4 places: on the first 6 numbers, on the second 6, on the third 6, on the fourth 6. second can be any one of 3 (3, 2, or 1) third can be any one of 2 (2 or 1) fourth digit can be 1 => 4 * 3 * 2 * 1 = 24, but this includes 4321 => total of 4 digit numbers = 23. Well to simplify it , lets consider the Number of places and lets try to figure out what are the possible numbers that can be assigned in each place to make a valid 4 digit number. In a similar way there are 10 4 = 10,00 possible four digit numbers. How many 4 - digit numbers can be formed from the digits 1,1,2,2,3,3,4,5?. A square number, also called a perfect square, is a figurate number of the form , where is an integer. Since, terminal digits are even. How many numbers can you make from given a set of individual digits, and how do make it a greatest number? Form all possible three digit number from 0,2 and 6. For the thousand place we have 5 options (1,2,3,4,5 ). so answer is 5^2*5=5^3. 12345: 22. The first digit from the left can be any of the 4 digits 1, 2, 4 or 5 Then the remaining 4 digits including '0' can be arranged in the other 4 places in 4! ways. From MS Word, I have done a MAIL MERGE, and some of the zip codes are 5 digit, while others are 9 digit, as in 12345-6789. Now we can form those unknown two position 2^5 way (number can be repeated. The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9). Three(3) digit numbers can be formed from the digits 0,1,3,5,7 and 8. In total you will find 5 × 24 = 120 possibilities. When rounding off numbers to a certain number of significant figures, do so to the nearest value. Effective Mathematics Tutor. Just imagine picking the digits in reverse. So there are 3*6*5*4 even numbers (or 3/7 of the total) and 4*6*5*4 odd numbers (or 4/7 of the total). answered • 04/04/14. The 7th digit. (ii) no digit is repeated. A real number can be expressed by a finite number of decimal digits only if it is rational and its fractional part has a denominator whose prime factors are 2 or 5 or both, because these are the prime factors of 10, the base of the decimal system. mark, the mark between intervals before the decimal point with big. com Email: [email protected] In how many different ways can you form a two digit number out of these digits. Write your number in words. if the difference of the original number and the new number is 45, find all numbers that satisfy the conditions. How many of will be even?. "The number of decimal digits in Fib(N) can be shown to be about 0. Since 0 cannot be first, remove it. 5-digit number is to be formed from the digits 1, 2, 3, 4, 5, 6, 7, 8, 9. In algorithm form: 1. Now if we take 126, of the remaining digits any can be the first digit of the number. Thousands digit can not have 0. 33 digit (any between the digits given different than what we picked for the 1st and 2d digit), 2 opportunities of choosing the fourth digit (any. digits cannot be repeated? Using the Fundamental Counting Principle: 2. For 4-digit even number, last digit has to be even. Since, terminal digits are even. There are four choices for the first digit (3, 5, 7, 9) and each of the choices can be followed by the other 6 digits in any order. How many 5-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9? Repeated digits are allowed. s from the Allowed digits = 1, 3, 5. Can you explain this answer? is done on EduRev Study Group by Quant Students. so for last digit = 2, total numbers=240. Three(3) digit numbers can be formed from the digits 0,1,3,5,7 and 8. 8 - if the number formed by the last 3 digits is divisible by 8. so the total combination would be 6*6*6*6, or 1296 four digit numbers. 3 digit numbers 1,2,3,4,5 Total number of digits = 5 Number of digits to be selected = 3 No repetition Total possible 3 digit number = 5P3 = 5 × 4 × 3 = 60 Numbers In view of the coronavirus pandemic, we are making LIVE CLASSES and VIDEO CLASSES completely FREE to prevent interruption in studies. I have numbers like 1100, 1002, 1022 etc. How many 5- digit numbers can be formed using the digits 1, 2, 3, 4, 5, 6, 7 if repetition of digits is not allowed? HOW OUR WEBSITE WORKS. Total numbers total digits = 10. Note: the word decimal can mean TWO things: 1. Well to simplify it , lets consider the Number of places and lets try to figure out what are the possible numbers that can be assigned in each place to make a valid 4 digit number. If a digit may be repeated in a number, how many three-digit numbers can be formed from the digits 2, 4, 6, and 7? How many of the digits are even? 3. ) "at least 5000" means the number goes from 5000 to 9999, but "divisible by 10" means the form of the number is xxx0, so the last digit is always 0. you can use any of remaining 8 digits in 10's place. The 6th digit is chosen from the remaining 5 numbers. How many three-digit numbers can be formed from the numerals in the set { 1 , 2 , 3 , 4 , 5 } if: a. The team has 9 players, but the coach does not want the pitcher to be one of the first four. How many different 3 digit numbers can be formed using the digits 1,2,4 and 8 when repetition is not allowed? - Answered by a verified Math Tutor or Teacher We use cookies to give you the best possible experience on our website. If units position can not be zero? Answer by Edwin McCravy(17550) (Show Source):. Anil Kumar 52,920 views. How many of these will be even?Let. gl/9WZjCW Using all digits `2,3, 4,5,6` how many even numbers can be formed. Number > 30000 2. Write your number in words. A baseball coach is determining the batting order for the team. If the digits were stored in an uncompressed ascii text file, the combined size of the decimal and hexadecimal digits would be 8. The PBX handles calls between these extensions. First digit odd: 3 digits. Total numbers total digits = 10. The number of four digit numbers that can be formed using six digits is ⁶P₄ = 6 * 5 * 4 * 3 = 360. Three(3) digit numbers can be formed from the digits 0,1,3,5,7 and 8. Restaurants can also open, provided they practise safe distancing. 3 digit numbers 1,2,3,4,5 Total number of digits = 5 Number of digits to be selected = 3 No repetition Total possible 3 digit number = 5P3 = 5 × 4 × 3 = 60 Numbers In view of the coronavirus pandemic, we are making LIVE CLASSES and VIDEO CLASSES completely FREE to prevent interruption in studies. DuPont (NYSE: DD) today announced financial results for the first quarter 2020. How many 3-digit numbers can be formed from the digits 1,2,3,4 and 5 assuming repetition of digits is not allowed. For example if input number is 234, possible words which can be formed are (Alphabetical order): adg adh adi aeg aeh aei afg afh afi bdg bdh bdi beg beh bei bfg bfh bfi cdg cdh cdi ceg ceh cei cfg cfh cfi. How many different four digit numbers can be formed from the digits 1 2 3 4 5 6 from STAT 218 at Ohio State University. Answers: 1 on a question: The digits of a two-digit number are interchanged to form a new two-digit number. = 4 × 6 × 5 × 4 = 480 Case :(ii) First digit is 2 , second digit starts from 3 , so it can be 3,4,5,6 so 4 possibilities. In order for the number to be even, the '2' must be the last digit. you can use any of remaining 9 digits in 100's place. s from the Allowed digits = 1, 3, 5. As can the third. Now, Number of 1 digit Numbers = 4 Number of 2 digit Numbers = 4*3=12 Number of 3 digit Numbers = 4*3*2=24 Number of 4 digit Numbers = 4*3*2*1=24 therefore required result will be = 4+12+24+24=64. 5, one fifth is 0. that is (1,3,7,8,9) and (4 ,6) I am going to simplify the question and say that no digit can be used twice and the 4 and 6 must be included. First digit odd: 3 digits. If we change the order to 207, this represents a. How many 4 - digit numbers can be formed from the digits 1,1,2,2,3,3,4,5?. Number of 7 digit numbers = 7!3!×2! = 420 But out of these 420 numbers, there are some numbers which begin with '0' and they are not 7-digit numbers. 8 - if the number formed by the last 3 digits is divisible by 8. The first place can be any of 10 digits. The first digit from the left can be any of the 4 digits 1, 2, 4 or 5 Then the remaining 4 digits including '0' can be arranged in the other 4 places in 4! ways. Units place is filled with only '2' and the remaining three places can be filled in ⁵P₃ ways. This can be done by. Now for each of the 100 possible choices of a two digit number you can append any of the ten digits to make a three digit number. Again there are 24 + 18 = 42 ways to create an even 5 digit integer. I can tell you how many numbers there would be. Now, the first 2 digits of the 4 digit number can be filled in 5 x 5 ways as each place can be filled by 5 digits with repetition so max is 5x5=25 cases for each of 5 cases of last 2 digits So, desired answer = 5 x 5 x 5= 125 (answer). gl/9WZjCW Using all digits `2,3, 4,5,6` how many even numbers can be formed. Always solve it without replacement, unless the problem specifically asks otherwise) Example 4: How many 4-digits number can be formed out of 0,1,2,3,5,7 and 9, if each digit can be used more than once (with repetition). How many numbers of three digits can be formed using the digits 1, 2, 3, 4, 5, without repetition of digits is x. There are four choices for the first digit (3, 5, 7, 9) and each of the choices can be followed by the other 6 digits in any order. A number is odd if the One's digit is odd. digits, ones, tens, expanded form. 1) a) How many 4-digit numbers can be formed by using the digits 1,2,3,4,5,6,7,8,9 when all digits of the 4-digit number are unique ie, the digits cannot be repeated? (ii) the digits can be repeated? b) Among the 4-digit numbers from part(a) (), how many of them will be an even number?. 0 ( 1 Vote ). c) How many 5-digit odd numbers can. Suppose that you are going to write one of these 4 digit combinations. How many 3 digit numbers can be formed from the digits 12345 so that the same digit is not used twice in a row? The first digit may be any of 5 possibilities. Example 3: How many 2 digit numbers can you make using the digits 1, 2, 3 and 4 without repeating the digits? This time we want to use 2 digits at the time to make 2 digit numbers. Ans: 502 9 digit no- 1,2,3,4,5,6,7,8,9 can be formed in only 1 way= 9C0 8 digit no can be formed by taking out one no. of numbers with sum 2 = a million No. So the total number of 4 digit numbers under these conditions is: 4 X 10 X 10 X 10, or 4000. 5040 different 4 digit numbers can be formed with the digits 123456789. Each digit can be any of five numbers, so 5^4=625 different numbers. The last digit determines the number's parity. For the hundredth place digit all 6 possibilities exist. For the third digit you are picking from 2 digits. The primary advantage of PBXs was cost savings on internal phone calls: handling the. How many different 3 digit numbers can be formed using the digits 1,2,4 and 8 when repetition is not allowed? - Answered by a verified Math Tutor or Teacher We use cookies to give you the best possible experience on our website. I am also given a list of numbers say {2,4,8,9}. The first place can be. You can start with any number from 0-9. If the 3-digit numbers formed end with 0, then we have 5 choices for the hundreds digit. This is assuming that no digits are repeated with each combination. Answer : 120 * It is a Combinations and Permutations question * n = [1,2,3,4,5,6] = 6 * r=3 Formula for “Without repetition” : Sample Python Verification :. The first digit of the 3-digits can take 7 distinct values: 1, 2, 3, 4, 5, 7, 9. If you CAN repeat digits: The first digit can only be 2, 4, 6, or 8, so there are 4 ways to pick the first digit. For example, in the rather small integer 1379 we can find as many as thirty-one primes: 3 7 13 17 19 31 37 71 73 79 97 137. How many 4 - digit numbers can be formed using the digits 0,1,2,3,4,5,6 if repetitions are not allowed?. There are 120 ways to form 4-digit even numbers from the given digits. This discussion on How many five digit numbers can be formed with the digits 1, 2, 3, 4 and 5 if no digit can be repeated?a)10b)50c)60d)120e)720Correct answer is. To find the number of numbers greater than 1200 that can be formed with 6 digits 3, 4,5,6 and 8 without repetition: We see that all the digits 3,4,5, 6 and 8 are greater than the digits 1 and 2. 1x4x4x4 = 64. There are four choices for the first digit (3, 5, 7, 9) and each of the choices can be followed by the other 6 digits in any order. The last digit can be 0,2,4, or 6 (4 possibilities), and after you've chosen that, theres 7 possibilities for the first digit and 6 possibilities for the second digit, which makes 4*7*6 = 168. Well to simplify it , lets consider the Number of places and lets try to figure out what are the possible numbers that can be assigned in each place to make a valid 4 digit number. First count all the 5-digit numbers: There are 5 possible first digits. So there will be three mutually exclusive events in. For 3 or 5, the last digit can be 0 or 4, and the middle two any of the remaining 3 in 3P2 = 6 ways. so the total combination would be 6*6*6*6, or 1296 four digit numbers. If those numbers are included it brings the count up to 36. The last digit determines the number's parity. For the first digit you are picking from 2 digits. How many five digit numbers can be formed from the digits, 2, 3, 4, 5, 6, 7, 8 and 9 with no digit repeated? How many 3-digit even numbers can be made using the. 0 INTRODUCTIONPrivate branch exchange system (PBXs) operates as a connection within private organizations usually a business. Note: As Paul noted, this will give you. Of the given digits, two is the only even digit. How many different 3 digit numbers can be formed using the digits 1,2,4 and 8 when repetition is not allowed? - Answered by a verified Math Tutor or Teacher We use cookies to give you the best possible experience on our website. If digits can be repeated, but the first digit cannot be. so ans is 125. Each digit can be any of five numbers, so 5^4=625 different numbers. Ross, which at the time reported monthly sales (a practice that has since ceased), posted 4% comparable sales growth during the month ended Oct. Can you see a pattern in the diagram below? 4 9 7, 5 4 8, 6 0 1, 3 7 2. If you CAN repeat digits: The first digit can only be 2, 4, 6, or 8, so there are 4 ways to pick the first digit. How many of will be even?. Question 887986: how many even four digit numbers can be formed from the digits 0,1,2,5,6 and 9. How many numbers can be formed without repeats. There are four digits and each of them can be from 0 to 9, for 10 possible choices per digit. 5040 different 4 digit numbers can be formed with the digits 123456789. Since each digit choice is independent, we just multiply all these choices together:. Solution for How many three-digit numbers can be formed of the digits 1, 2, 3, 4, 5, and 6 if each digit can only be used once?. Second digit can be only pick from the rest, so the number of choices only 5. In other words, we have 5 possible choices for the ones digit. Question 299130: How many four-digit odd numbers less than 6000 can be formed using the digits 2,4,6,7,8,9? Answer by Edwin McCravy(17789) (Show Source):. 0,1,2,3,4,5 can be each in 4 places: on the first 6 numbers, on the second 6, on the third 6, on the fourth 6. Using the digits 1, 4, 6, and 9, how many 2-digit whole numbers can be formed if repetitions are not permitted? 5. TCS Question Solution - how many four digit number can be formed with 12345 that r divisible by 4 and digits r not repeated. total numbers formed = 9 × 9 × 8 × 7 = 4536. The number of such numbers beginning with '0'. First count all the 5-digit numbers: There are 5 possible first digits. The 7th digit. a total of 125 combinations are possible (5*5*5) if set 1,2,3,4,5. Depends on whether you can repeat digits or not. out of these six digits without repetition 4 digits can be selected as 6p4. you can use any of remaining 7 digits in 1's place. Now, since the second last digit is also even. How many four digit numbers can be formed using the digits 5, 6, 7, 8, 9 if any of the digits can occur more than once?? Help with permutation!!. So, first digit must be 6 only and the remaining three places can be filled by one of all the four digits. In a similar way there are 10 4 = 10,00 possible four digit numbers. Image source: The Motley Fool. How many 4-digit numbers can be formed using only the digits {1,2,3} if repetition is allowed and the number must contain the digit 3 somewhere. So there will be three mutually exclusive events in. find how many six-digit numbers can be formed from the digits 2,3,4,5,6,7 (with repetitions) if a) numbers formed must be even b) the numbers formed must be divisble by 25 c) the odd digits must occupy even position (2nd, 4th, asked by anna on April 27, 2019; College. Question 299130: How many four-digit odd numbers less than 6000 can be formed using the digits 2,4,6,7,8,9? Answer by Edwin McCravy(17789) (Show Source):. 83); adjusted EPS of $0. First digit can be 3, 4, or 5. Final digit can be any unused digit: 4 digits: 3 * 3 * 4 = 36. There are only 5 numbers (or b-ball player) and you can choose to arrange only 3 of them in any order. Next digit even: 3 digits. We need to pay attention to the first and the last digit. Finish: 1:12 AM (JST) August 3, 2010. This can be done in 9C1 ways as after eliminating any one no. 6 is written as 5. There are 10,000 possible combinations that the digits 0-9 can be arranged to form a 4-digit pin code. The first place can be any of 10 digits. For each digit position there are 7 possible digits, so the total number is 7*7*7*7*4=9,604, because the last digit has to be odd, and that means it can only be 1, 3, 5 or 7. Why they are adding $1+2+5+6$?. The Services tailwind drives another strong quarter for Apple, as Services growth remains in the double-digits. How many 5-digit numbers can be formed from the digits 1, 3, 4, 5, 6, 8, and 9 if the following is true? (a) each digit may be used once in each number (b) each digit. = 4 × 6 × 5 × 4 = 480 Case :(ii) First digit is 2 , second digit starts from 3 , so it can be 3,4,5,6 so 4 possibilities. How many of will be even?. so the total combination would be 6*6*6*6, or 1296 four digit numbers. If those numbers are included it brings the count up to 36. 35 x 10 4) example: Round to 2 significant figures: 1. # This code is contributed by "Sharad_Bhardwaj". Let unit digit be 1 EDIT : [Courtesy Robert Toop] Then, number of numbers =8(1000's digit except. How many 3 digit numbers can be formed from the digits 12345 so that the same digit is not used twice in a row? The first digit may be any of 5 possibilities. The smallest digit is in the thousand place. Always solve it without replacement, unless the problem specifically asks otherwise) Example 4: How many 4-digits number can be formed out of 0,1,2,3,5,7 and 9, if each digit can be used more than once (with repetition). Final digit can be any unused digit: 4 digits: 3 * 3 * 4 = 36. 83); adjusted EPS of $0. How many 5-digit numbers can be formed from the digits 1, 3, 4, 5, 6, 8, and 9 if the following is true? (a) each digit may be used once in each number (b) each digit. I have numbers like 1100, 1002, 1022 etc. 1) a) How many 4-digit numbers can be formed by using the digits 1,2,3,4,5,6,7,8,9 when all digits of the 4-digit number are unique ie, the digits cannot be repeated? (ii) the digits can be repeated? b) Among the 4-digit numbers from part(a) (), how many of them will be an even number?. This falls further behind N as N gets larger. I think it's 256 as the number of possibilities keeps doubling for every starting number. Numbers which are divisible by 4 can be determined by the last two digits. Now if any one digit of third and fourth digit can be 0 as no digit is. 6, 2001, down from high-single-digit marks in the. I'm not printing out a list. Below you'll find many printable worksheets and lessons for reviewing 4-digit place value with your students. gl/9WZjCW Using all digits `2,3, 4,5,6` how many even numbers can be formed. Any of the digits can be used any number of times. Since each digit choice is independent, we just multiply all these choices together:. Find the sum of all four digit numbers formed using the digits 1,2,3,4, 5, each digit appearing at most once. Since it's a 4 digit number, each digit will appear $6= 24/4$ times in each of units, tens, hundreds, and thousands place. so for last digit = 2, total numbers=240 Similarly for 4 and 6When last digit = 4, total no. Thousands digit can not have 0. So 4 numbers. How many 4 - digit numbers can be formed from the digits 1,1,2,2,3,3,4,5?. We need to pay attention to the first and the last digit. No digit can appear more than twice. As can the third. hundreds and tens, we get exactly two numbers from $1-6$ which placed at ones digit will make the number divisible by $3$. How many 3-digit numbers can be formed from the digits 1,2,3,4 and 5 assuming repetition of digits is not allowed. Digits is a phenomenal and truly game-changing product. Break the problem down by the number of digits in the answer. Four-digit integers are formed using the digits 2, 3, 4 and 5. For your second question. = 4 × 6 × 5 × 4 = 480 Case :(ii) First digit is 2 , second digit starts from 3 , so it can be 3,4,5,6 so 4 possibilities. 4x120 = 480. Unit digit is restricted to 1,3,5,7,9. 125*5 = 625 such numbers can be formed. 3, 4 (Method 1)Find the number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated. Because there are four numbers in the combination, the total number of possible combinations is 10 choices for each of the four numbers. The number of four digit numbers can be calculated by using rule of combination. 1, and one fiftieth is 0. How many 4-digit even numbers can be formed using digits 1,2,3,5 using each digit once? - 2684337. The first digit can take on nine values, from 1 to 9. Alok is attending a workshop 'How to do more with less and today's theme is Working with fewer digits. 3, 4, 6 - 346, 364, 436, 463, 634, 643. 2 N, and the average value of a decimal digit is (0+1++8+9)/10 = 4·5. Answer : 120 * It is a Combinations and Permutations question * n = [1,2,3,4,5,6] = 6 * r=3 Formula for “Without repetition” : Sample Python Verification :. Therefore, the sum of digits in the units place is $6(1+2+5+6)=84$. you can use any of remaining 9 digits in 100's place. // This code is contributed by Anshika Goyal. How many vehicle registration plate numbers can be formed with digits 1,2,3,4,5 (no digit being repeated)if it's given that registration number can have 1 - 5320569. 3 x 3 x 2 x1 = 18. Question: How many numbers with two or more digits can be formed with the digits 1,2,3,4,5,6,7,8,9, so that in every such number, each digit is used at most once and the digits appear in the ascending order?. How many 4 - digit numbers can be formed from the digits 1,1,2,2,3,3,4,5?. unfortunately each number will be greater than 500. Answer / sam. Final digit can be any unused digit: 4 digits: 3 * 3 * 4 = 36. From MS Word, I have done a MAIL MERGE, and some of the zip codes are 5 digit, while others are 9 digit, as in 12345-6789. I would like to have the individual digits, for example for the first number 1100 I want to have 1, 1, 0, 0. So the total number of 4 digit numbers under these conditions is: 4 X 10 X 10 X 10, or 4000. So last digit is 8, that can be selected in 1 way. 12 of them are odd, also 12 of them are greater than 300, and 4 of them are divisible by 3. We need to have at least two digits to make a number set. How many vehicle registration plate numbers can be formed with digits 1,2,3,4,5 (no digit being repeated)if it's given that registration number can have 1 - 5320569. The given numbers are 1, 2, 3, 4, 5, 6, 7, 8, 9. 1x4x4x4 = 64. First of the 4-digit number can be any one of the 4. What are the 1st, 13th, 49th and 60th words?. last 2 digits divisible by 4 are 12,32,44,52,24 and remaining 2 digits can be arranged in 5^2 ways as repetition is permitted. Question: How many 6-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 if repetitions are allowed? Permutations with Repetition:. We multiply them to get the number of ways to get the 4-digit number. 6 digit number with 3 possibilities for every digit, 3^6 unless am tard and read can't lol I took it literally, as in only 3 letters and 3 digits are used (so say 0,5, and 9) not 0-9 and a-z. For the thousand place we have 5 options (1,2,3,4,5 ). If you CAN repeat digits: The first digit can only be 2, 4, 6, or 8, so there are 4 ways to pick the first digit. Use scissors to cut out the place value squares (ones. 132 is the smallest number which is the sum of all of the 2-digit numbers that can be formed with its digits. gl/9WZjCW Using all digits `2,3, 4,5,6` how many even numbers can be formed. that is (1,3,7,8,9) and (4 ,6) I am going to simplify the question and say that no digit can be used twice and the 4 and 6 must be included. 7 3 6, 4 8 5, 0 3 7. You can now earn points by answering the unanswered questions listed. Number of 7 digit numbers = 7!3!×2! = 420 But out of these 420 numbers, there are some numbers which begin with '0' and they are not 7-digit numbers. A square number, also called a perfect square, is a figurate number of the form , where is an integer. One byte or eight bits can produce 256 distinctive combinations of numbers, letters, symbols and characters. The square numbers for , 1, are 0, 1, 4, 9, 16, 25, 36, 49, A plot of the first few square numbers represented as a sequence of binary bits is shown above. of digits of the number to be formed at run-time). The total number of 5-digit numbers, then, is 4· 4! = 4· 24 = 96. The top portion shows to , and the bottom shows the next 510 values. How many of will be even?. Since you can repeat the digits the NUMBER of 4 digit combinations is relatively easy to calculate. In order for the number to be even, the '2' must be the last digit. Number of even numbers = ⁵P₃ = 60. Similarly, the sixth, seventh and eighth digits together must be divisible by eight according to the rule for divisibility by eight. Latest TCS Aptitude Question SOLUTION: How many motor vehicles registration number plates can be formed with the digits 1, 2, 3, 4, and 5(no digits being repeated) if. Thus, for example, one half is 0. In a similar way there are 10 4 = 10,00 possible four digit numbers. The number of ways to write to digit numbers divisible by 4 by using 1,2,3,4,5 are four, they are 12 ,24, 32,52. Restaurants can also open, provided they practise safe distancing. You are free to chose first two digits then you can have your last digit in two numbers. A numerical digit is a single symbol (such as "2" or "5") used alone, or in combinations (such as "25"), to represent numbers (such as the number 25) according to some positional numeral systems. of ways in which 4 letters can be posted in 5 letter boxes in 4 5 ways. Then there will be 4 ways to choose the first digit. The hints above describe two possible numbers. For the hundredth place digit all 6 possibilities exist. Different Ways to Represent 3-Digit Numbers and write numbers to 1000 using base-ten blocks and expanded form. Our website has a team of. None of the digits is 9. We consider that each digit is selected independently of the others. How many numbers of three digits can be formed using the digits 1, 2, 3, 4, 5, without repetition of digits is x. Since, terminal digits are even. How many different four digit numbers can be formed from the digits 1 2 3 4 5 6 from STAT 218 at Ohio State University. This will give 4 x 6! ways, or 4 x 6 x 5 x 4 x 3 x 2 x 1 ways. The total is 2 * 2 * 6 = 24. 1, 4 How many 5–digit telephone numbers can be constructed using the digits 0 to 9 if each number starts with 67 and no digit appears more than once? The telephone number is of 5 digits and first 2 numbers are 6 and 7 Hence number is of the form Digits between 0 to 9 = 0, 1,. The number of different 4-digit numbers without repeating digits is 5*4*3*2 = 120. 4*4*3*2*1 1(last digit is fix)=96 simillarly for 2,3,4,5 we will get total 96. The greates digit is in the ones place. Numbers are expressed in base 10. that is there are five possibilities for first place ( The first place can be either 1 or 2 or 3 or 4 or 5) and same is the case with second and the third. You can put this solution on YOUR website! 2,4,6,7,8,9 We choose the fourth digit first: There are 2 ways to select the fourth digit, either 7 or 9, so that the number will be odd. For a number to be multiple of 3, sum of digits should be multiple of 3. see here by using the given digits we can form single digit nos. find how many six-digit numbers can be formed from the digits 2,3,4,5,6,7 (with repetitions) if a) numbers formed must be even b) the numbers formed must be divisble by 25 c) the odd digits must occupy even position (2nd, 4th, asked by anna on April 27, 2019; College. Final digit can be any unused digit: 4 digits: 3 * 3 * 4 = 36. Ans: 502 9 digit no- 1,2,3,4,5,6,7,8,9 can be formed in only 1 way= 9C0 8 digit no can be formed by taking out one no. 1, and one fiftieth is 0. from the series, it continues to remain in ascending order. One byte or eight bits can produce 256 distinctive combinations of numbers, letters, symbols and characters. So, basically, you have every number from 0000 to 9999. you can use any of remaining 8 digits in 10's place. We need to have at least two digits to make a number set. the number's last two digits can be any. 1Q20 GAAP EPS from continuing operations of $(0. Now, we can form twenty four four-digit numbers by using each of these digits only once. As repetition is allowed, the second digit can also take 7 distinct values, and the. Now for each of the 100 possible choices of a two digit number you can append any of the ten digits to make a three digit number. There are four ways to form such a number. first place can be filled in 3 ways , 2nd place in 4 ways , 3rd in four ways and the fourth in four ways Total such numbers = 3 x 4 x 4 x 4 = 192 Now consider numbers starting with 4 and hundreds place either 1 or 2 (as the number has to be less than 4321) So again for such numbers , first place can be filled in 1 way, 2nd place in 2 ways. Question 1 : Count the numbers between 999 and 10000 subject to the condition that there are (i) no restriction. Since it's a 4 digit number, each digit will appear $6= 24/4$ times in each of units, tens, hundreds, and thousands place. = 4 × 6 × 5 × 4 = 480 Case :(ii) First digit is 2 , second digit starts from 3 , so it can be 3,4,5,6 so 4 possibilities. Anil Kumar 52,920 views. hey sir i am having problem in splitting a number into its digits if i use remainder and division operation then i can split a number and print it in reverse order but dont know how to split that number and print that in correct order here is my program #include using namespace std; int main() {int x=12345,r,c=1; while(c<=5){r=x%10; x. INTRODUCTIONThe VLSI was an important pioneer in the electronic design automation industry. 3467 x 10 4 (Answer: 2. the above answer 6 is correct but the 4 digit numbers are (3412,4312,3124,1324,1432,4132). If words are formed by taking only 4 at a time out of the letters of the word PHYSICS, then the number of words in which Y occurs, is 288. The first digit can be any of #1# through #9# and can be selected in nine different ways. How many 5- digit numbers can be formed using the digits 1, 2, 3, 4, 5, 6, 7 if repetition of digits is not allowed? HOW OUR WEBSITE WORKS. & 4 digit nos. To form numbers greater than 56000 using the digits 4,5,6,7,8 without repetition can be done (1)Taking first digit as 5 OR (2) first digit greater than 5 (1) If the first digit is 5 can be done in 1 way The second digit without repetition can be done in 3 ways ( it can not be 4) Rest of the 3 digits can be done in 3! = 6 ways Therefore Taking first digit as 5 numbers greater than 56000 can be. for 4 digit number 0 can not be used in 1000's place. 1, 4 How many 5–digit telephone numbers can be constructed using the digits 0 to 9 if each number starts with 67 and no digit appears more than once? The telephone number is of 5 digits and first 2 numbers are 6 and 7 Hence number is of the form Digits between 0 to 9 = 0, 1,. 0 ( 1 Vote ). To create a 5 digit number with 3, 4, 6, 8, 9. decimal = a decimal number = a number that has digits after the decimal point 2. the number's last two digits can be any. Hint: it may be easier to first count the numbers that don't contain the digit 3. How many 5 digit numbers can be made from the digits 1,3,4,6,7,8,9 if the 4 and 6 must be used at least once. There are 3 choices for the 2nd digit, 2 choices for the 3rd digit, and one digit remaining for the 4th digit. Hence, 64 - 1 = 63. Since each digit choice is independent, we just multiply all these choices together:. Note that this does not include digits formed by taking the same digit twice as 11, 22, 33, 44, 55, and 66. Cut out the number boxes and paste them next to the correct place value blocks. Start : 6:19 PM (JST) May 4, 2010. of 4 digit numbers that can be formed are 6 x 6 x 6 x 6 = 1296. For your second question. Next we choose the first digit: There are 2 ways to select the fourth digit, either 2 or 4, so that the number will be less than 6000. How many different 3 digit numbers can be formed using the digits 1,2,4 and 8 when repetition is not allowed? - Answered by a verified Math Tutor or Teacher We use cookies to give you the best possible experience on our website. ) 7 - there is no good trick for 7. Thousands digit can not have 0. Third digit can be only pick from the rest, so the number of choices only 4. The first digit of the 3-digits can take 7 distinct values: 1, 2, 3, 4, 5, 7, 9. As can the third. So the total number of 4 digit numbers under these conditions is: 4 X 10 X 10 X 10, or 4000. We need to have at least two digits to make a number set. Starting with even: First digit even: 3 digits. Advanced Micro Devices, Inc. How many 4 - digit numbers can be formed from the digits 1,1,2,2,3,3,4,5?. Can you explain this answer? is done on EduRev Study Group by Quant Students. Unfortunately, I need to reproduce the list.